3(2x+1)=17-2(x1)

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Solution for 3(2x+1)=17-2(x1) equation:



3(2x+1)=17-2(x1)
We move all terms to the left:
3(2x+1)-(17-2(x1))=0
We add all the numbers together, and all the variables
3(2x+1)-(-2x+17)=0
We multiply parentheses
6x-(-2x+17)+3=0
We get rid of parentheses
6x+2x-17+3=0
We add all the numbers together, and all the variables
8x-14=0
We move all terms containing x to the left, all other terms to the right
8x=14
x=14/8
x=1+3/4

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