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3(2x+1)=2(1-5)+6x+11
We move all terms to the left:
3(2x+1)-(2(1-5)+6x+11)=0
We add all the numbers together, and all the variables
3(2x+1)-(2(-4)+6x+11)=0
We multiply parentheses
6x-(2(-4)+6x+11)+3=0
We calculate terms in parentheses: -(2(-4)+6x+11), so:We get rid of parentheses
2(-4)+6x+11
determiningTheFunctionDomain 6x+11+2(-4)
We add all the numbers together, and all the variables
6x+3
Back to the equation:
-(6x+3)
6x-6x-3+3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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