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3(2x+1)=2(2x+5)+3
We move all terms to the left:
3(2x+1)-(2(2x+5)+3)=0
We multiply parentheses
6x-(2(2x+5)+3)+3=0
We calculate terms in parentheses: -(2(2x+5)+3), so:We get rid of parentheses
2(2x+5)+3
We multiply parentheses
4x+10+3
We add all the numbers together, and all the variables
4x+13
Back to the equation:
-(4x+13)
6x-4x-13+3=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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