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3(2x+1)=2(x+2)+1
We move all terms to the left:
3(2x+1)-(2(x+2)+1)=0
We multiply parentheses
6x-(2(x+2)+1)+3=0
We calculate terms in parentheses: -(2(x+2)+1), so:We get rid of parentheses
2(x+2)+1
We multiply parentheses
2x+4+1
We add all the numbers together, and all the variables
2x+5
Back to the equation:
-(2x+5)
6x-2x-5+3=0
We add all the numbers together, and all the variables
4x-2=0
We move all terms containing x to the left, all other terms to the right
4x=2
x=2/4
x=1/2
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