3(2x+1)=2+3(x-2)

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Solution for 3(2x+1)=2+3(x-2) equation: 



3(2x+1)=2+3(x-2)

We move all terms to the left:

3(2x+1)-(2+3(x-2))=0

We multiply parentheses

6x-(2+3(x-2))+3=0



We calculate terms in parentheses: -(2+3(x-2)), so:

2+3(x-2)

determiningTheFunctionDomain
3(x-2)+2

We multiply parentheses

3x-6+2

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We get rid of parentheses

6x-3x+4+3=0

We add all the numbers together, and all the variables

3x+7=0

We move all terms containing x to the left, all other terms to the right

3x=-7

x=-7/3

x=-2+1/3

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