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3(2x+1)=3(x+13)
We move all terms to the left:
3(2x+1)-(3(x+13))=0
We multiply parentheses
6x-(3(x+13))+3=0
We calculate terms in parentheses: -(3(x+13)), so:We get rid of parentheses
3(x+13)
We multiply parentheses
3x+39
Back to the equation:
-(3x+39)
6x-3x-39+3=0
We add all the numbers together, and all the variables
3x-36=0
We move all terms containing x to the left, all other terms to the right
3x=36
x=36/3
x=12
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