3(2x+1)=3(x-1)+14

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Solution for 3(2x+1)=3(x-1)+14 equation: 



3(2x+1)=3(x-1)+14

We move all terms to the left:

3(2x+1)-(3(x-1)+14)=0

We multiply parentheses

6x-(3(x-1)+14)+3=0



We calculate terms in parentheses: -(3(x-1)+14), so:

3(x-1)+14

We multiply parentheses

3x-3+14

We add all the numbers together, and all the variables

3x+11

Back to the equation:

-(3x+11)



We get rid of parentheses

6x-3x-11+3=0

We add all the numbers together, and all the variables

3x-8=0

We move all terms containing x to the left, all other terms to the right

3x=8

x=8/3

x=2+2/3

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