3(2x+1)=3(x-1)-2(x-3)

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Solution for 3(2x+1)=3(x-1)-2(x-3) equation: 



3(2x+1)=3(x-1)-2(x-3)

We move all terms to the left:

3(2x+1)-(3(x-1)-2(x-3))=0

We multiply parentheses

6x-(3(x-1)-2(x-3))+3=0



We calculate terms in parentheses: -(3(x-1)-2(x-3)), so:

3(x-1)-2(x-3)

We multiply parentheses

3x-2x-3+6

We add all the numbers together, and all the variables

x+3

Back to the equation:

-(x+3)



We get rid of parentheses

6x-x-3+3=0

We add all the numbers together, and all the variables

5x=0

x=0/5

x=0

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