3(2x+1)=3+2(2x+5)

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Solution for 3(2x+1)=3+2(2x+5) equation: 



3(2x+1)=3+2(2x+5)

We move all terms to the left:

3(2x+1)-(3+2(2x+5))=0

We multiply parentheses

6x-(3+2(2x+5))+3=0



We calculate terms in parentheses: -(3+2(2x+5)), so:

3+2(2x+5)

determiningTheFunctionDomain
2(2x+5)+3

We multiply parentheses

4x+10+3

We add all the numbers together, and all the variables

4x+13

Back to the equation:

-(4x+13)



We get rid of parentheses

6x-4x-13+3=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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