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3(2x+1)=4(3x-2)
We move all terms to the left:
3(2x+1)-(4(3x-2))=0
We multiply parentheses
6x-(4(3x-2))+3=0
We calculate terms in parentheses: -(4(3x-2)), so:We get rid of parentheses
4(3x-2)
We multiply parentheses
12x-8
Back to the equation:
-(12x-8)
6x-12x+8+3=0
We add all the numbers together, and all the variables
-6x+11=0
We move all terms containing x to the left, all other terms to the right
-6x=-11
x=-11/-6
x=1+5/6
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