3(2x+1)=4(3x-4)

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Solution for 3(2x+1)=4(3x-4) equation:



3(2x+1)=4(3x-4)
We move all terms to the left:
3(2x+1)-(4(3x-4))=0
We multiply parentheses
6x-(4(3x-4))+3=0
We calculate terms in parentheses: -(4(3x-4)), so:
4(3x-4)
We multiply parentheses
12x-16
Back to the equation:
-(12x-16)
We get rid of parentheses
6x-12x+16+3=0
We add all the numbers together, and all the variables
-6x+19=0
We move all terms containing x to the left, all other terms to the right
-6x=-19
x=-19/-6
x=3+1/6

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