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3(2x+1)=5+3(x-1)
We move all terms to the left:
3(2x+1)-(5+3(x-1))=0
We multiply parentheses
6x-(5+3(x-1))+3=0
We calculate terms in parentheses: -(5+3(x-1)), so:We get rid of parentheses
5+3(x-1)
determiningTheFunctionDomain 3(x-1)+5
We multiply parentheses
3x-3+5
We add all the numbers together, and all the variables
3x+2
Back to the equation:
-(3x+2)
6x-3x-2+3=0
We add all the numbers together, and all the variables
3x+1=0
We move all terms containing x to the left, all other terms to the right
3x=-1
x=-1/3
x=-1/3
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