3(2x+1)=7+2(4x-5)

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Solution for 3(2x+1)=7+2(4x-5) equation: 



3(2x+1)=7+2(4x-5)

We move all terms to the left:

3(2x+1)-(7+2(4x-5))=0

We multiply parentheses

6x-(7+2(4x-5))+3=0



We calculate terms in parentheses: -(7+2(4x-5)), so:

7+2(4x-5)

determiningTheFunctionDomain
2(4x-5)+7

We multiply parentheses

8x-10+7

We add all the numbers together, and all the variables

8x-3

Back to the equation:

-(8x-3)



We get rid of parentheses

6x-8x+3+3=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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