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3(2x+10)-2(x+1)=3(x+5)+2(x+2)
We move all terms to the left:
3(2x+10)-2(x+1)-(3(x+5)+2(x+2))=0
We multiply parentheses
6x-2x-(3(x+5)+2(x+2))+30-2=0
We calculate terms in parentheses: -(3(x+5)+2(x+2)), so:We add all the numbers together, and all the variables
3(x+5)+2(x+2)
We multiply parentheses
3x+2x+15+4
We add all the numbers together, and all the variables
5x+19
Back to the equation:
-(5x+19)
4x-(5x+19)+28=0
We get rid of parentheses
4x-5x-19+28=0
We add all the numbers together, and all the variables
-1x+9=0
We move all terms containing x to the left, all other terms to the right
-x=-9
x=-9/-1
x=+9
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