3(2x+10)-32=6+2(3x-4)

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Solution for 3(2x+10)-32=6+2(3x-4) equation: 



3(2x+10)-32=6+2(3x-4)

We move all terms to the left:

3(2x+10)-32-(6+2(3x-4))=0

We multiply parentheses

6x-(6+2(3x-4))+30-32=0



We calculate terms in parentheses: -(6+2(3x-4)), so:

6+2(3x-4)

determiningTheFunctionDomain
2(3x-4)+6

We multiply parentheses

6x-8+6

We add all the numbers together, and all the variables

6x-2

Back to the equation:

-(6x-2)



We add all the numbers together, and all the variables

6x-(6x-2)-2=0

We get rid of parentheses

6x-6x+2-2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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