3(2x+10)=7(x+1)+21

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Solution for 3(2x+10)=7(x+1)+21 equation: 



3(2x+10)=7(x+1)+21

We move all terms to the left:

3(2x+10)-(7(x+1)+21)=0

We multiply parentheses

6x-(7(x+1)+21)+30=0



We calculate terms in parentheses: -(7(x+1)+21), so:

7(x+1)+21

We multiply parentheses

7x+7+21

We add all the numbers together, and all the variables

7x+28

Back to the equation:

-(7x+28)



We get rid of parentheses

6x-7x-28+30=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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