3(2x+100)=20x-2(2x+100)

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Solution for 3(2x+100)=20x-2(2x+100) equation: 



3(2x+100)=20x-2(2x+100)

We move all terms to the left:

3(2x+100)-(20x-2(2x+100))=0

We multiply parentheses

6x-(20x-2(2x+100))+300=0



We calculate terms in parentheses: -(20x-2(2x+100)), so:

20x-2(2x+100)

We multiply parentheses

20x-4x-200

We add all the numbers together, and all the variables

16x-200

Back to the equation:

-(16x-200)



We get rid of parentheses

6x-16x+200+300=0

We add all the numbers together, and all the variables

-10x+500=0

We move all terms containing x to the left, all other terms to the right

-10x=-500

x=-500/-10

x=+50

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