3(2x+12)=-2(2x-4)+x

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Solution for 3(2x+12)=-2(2x-4)+x equation: 



3(2x+12)=-2(2x-4)+x

We move all terms to the left:

3(2x+12)-(-2(2x-4)+x)=0

We multiply parentheses

6x-(-2(2x-4)+x)+36=0



We calculate terms in parentheses: -(-2(2x-4)+x), so:

-2(2x-4)+x

We add all the numbers together, and all the variables

x-2(2x-4)

We multiply parentheses

x-4x+8

We add all the numbers together, and all the variables

-3x+8

Back to the equation:

-(-3x+8)



We get rid of parentheses

6x+3x-8+36=0

We add all the numbers together, and all the variables

9x+28=0

We move all terms containing x to the left, all other terms to the right

9x=-28

x=-28/9

x=-3+1/9

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