3(2x+12)=-2(x-4)3+x

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Solution for 3(2x+12)=-2(x-4)3+x equation: 



3(2x+12)=-2(x-4)3+x

We move all terms to the left:

3(2x+12)-(-2(x-4)3+x)=0

We multiply parentheses

6x-(-2(x-4)3+x)+36=0



We calculate terms in parentheses: -(-2(x-4)3+x), so:

-2(x-4)3+x

We add all the numbers together, and all the variables

x-2(x-4)3

We multiply parentheses

x-6x+24

We add all the numbers together, and all the variables

-5x+24

Back to the equation:

-(-5x+24)



We get rid of parentheses

6x+5x-24+36=0

We add all the numbers together, and all the variables

11x+12=0

We move all terms containing x to the left, all other terms to the right

11x=-12

x=-12/11

x=-1+1/11

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