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3(2x+12)=2(10-x)-5x
We move all terms to the left:
3(2x+12)-(2(10-x)-5x)=0
We add all the numbers together, and all the variables
3(2x+12)-(2(-1x+10)-5x)=0
We multiply parentheses
6x-(2(-1x+10)-5x)+36=0
We calculate terms in parentheses: -(2(-1x+10)-5x), so:We get rid of parentheses
2(-1x+10)-5x
We add all the numbers together, and all the variables
-5x+2(-1x+10)
We multiply parentheses
-5x-2x+20
We add all the numbers together, and all the variables
-7x+20
Back to the equation:
-(-7x+20)
6x+7x-20+36=0
We add all the numbers together, and all the variables
13x+16=0
We move all terms containing x to the left, all other terms to the right
13x=-16
x=-16/13
x=-1+3/13
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