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3(2x+12)=3(x-10)
We move all terms to the left:
3(2x+12)-(3(x-10))=0
We multiply parentheses
6x-(3(x-10))+36=0
We calculate terms in parentheses: -(3(x-10)), so:We get rid of parentheses
3(x-10)
We multiply parentheses
3x-30
Back to the equation:
-(3x-30)
6x-3x+30+36=0
We add all the numbers together, and all the variables
3x+66=0
We move all terms containing x to the left, all other terms to the right
3x=-66
x=-66/3
x=-22
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