3(2x+2)+3(4z+2)=117

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Solution for 3(2x+2)+3(4z+2)=117 equation:


Simplifying
3(2x + 2) + 3(4z + 2) = 117

Reorder the terms:
3(2 + 2x) + 3(4z + 2) = 117
(2 * 3 + 2x * 3) + 3(4z + 2) = 117
(6 + 6x) + 3(4z + 2) = 117

Reorder the terms:
6 + 6x + 3(2 + 4z) = 117
6 + 6x + (2 * 3 + 4z * 3) = 117
6 + 6x + (6 + 12z) = 117

Reorder the terms:
6 + 6 + 6x + 12z = 117

Combine like terms: 6 + 6 = 12
12 + 6x + 12z = 117

Solving
12 + 6x + 12z = 117

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + 6x + -12 + 12z = 117 + -12

Reorder the terms:
12 + -12 + 6x + 12z = 117 + -12

Combine like terms: 12 + -12 = 0
0 + 6x + 12z = 117 + -12
6x + 12z = 117 + -12

Combine like terms: 117 + -12 = 105
6x + 12z = 105

Add '-12z' to each side of the equation.
6x + 12z + -12z = 105 + -12z

Combine like terms: 12z + -12z = 0
6x + 0 = 105 + -12z
6x = 105 + -12z

Divide each side by '6'.
x = 17.5 + -2z

Simplifying
x = 17.5 + -2z

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