3(2x+2)+x+4=66

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Solution for 3(2x+2)+x+4=66 equation: 



3(2x+2)+x+4=66

We move all terms to the left:

3(2x+2)+x+4-(66)=0

We add all the numbers together, and all the variables

x+3(2x+2)-62=0

We multiply parentheses

x+6x+6-62=0

We add all the numbers together, and all the variables

7x-56=0

We move all terms containing x to the left, all other terms to the right

7x=56

x=56/7

x=8

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