3(2x+2)+x+5=3(2x+2)+x+5=-10

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Solution for 3(2x+2)+x+5=3(2x+2)+x+5=-10 equation: 



3(2x+2)+x+5=3(2x+2)+x+5=-10

We move all terms to the left:

3(2x+2)+x+5-(3(2x+2)+x+5)=0

We add all the numbers together, and all the variables

x+3(2x+2)-(3(2x+2)+x+5)+5=0

We multiply parentheses

x+6x-(3(2x+2)+x+5)+6+5=0



We calculate terms in parentheses: -(3(2x+2)+x+5), so:

3(2x+2)+x+5

We add all the numbers together, and all the variables

x+3(2x+2)+5

We multiply parentheses

x+6x+6+5

We add all the numbers together, and all the variables

7x+11

Back to the equation:

-(7x+11)



We add all the numbers together, and all the variables

7x-(7x+11)+11=0

We get rid of parentheses

7x-7x-11+11=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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