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3(2x+2)-(3x-4)+2x=12
We move all terms to the left:
3(2x+2)-(3x-4)+2x-(12)=0
We add all the numbers together, and all the variables
2x+3(2x+2)-(3x-4)-12=0
We multiply parentheses
2x+6x-(3x-4)+6-12=0
We get rid of parentheses
2x+6x-3x+4+6-12=0
We add all the numbers together, and all the variables
5x-2=0
We move all terms containing x to the left, all other terms to the right
5x=2
x=2/5
x=2/5
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