3(2x+2)-4=3(x+1)

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Solution for 3(2x+2)-4=3(x+1) equation: 



3(2x+2)-4=3(x+1)

We move all terms to the left:

3(2x+2)-4-(3(x+1))=0

We multiply parentheses

6x-(3(x+1))+6-4=0



We calculate terms in parentheses: -(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We add all the numbers together, and all the variables

6x-(3x+3)+2=0

We get rid of parentheses

6x-3x-3+2=0

We add all the numbers together, and all the variables

3x-1=0

We move all terms containing x to the left, all other terms to the right

3x=1

x=1/3

x=1/3

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