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3(2x+2)-5-2x=6(x-5)+7+2x
We move all terms to the left:
3(2x+2)-5-2x-(6(x-5)+7+2x)=0
We add all the numbers together, and all the variables
-2x+3(2x+2)-(6(x-5)+7+2x)-5=0
We multiply parentheses
-2x+6x-(6(x-5)+7+2x)+6-5=0
We calculate terms in parentheses: -(6(x-5)+7+2x), so:We add all the numbers together, and all the variables
6(x-5)+7+2x
determiningTheFunctionDomain 6(x-5)+2x+7
We add all the numbers together, and all the variables
2x+6(x-5)+7
We multiply parentheses
2x+6x-30+7
We add all the numbers together, and all the variables
8x-23
Back to the equation:
-(8x-23)
4x-(8x-23)+1=0
We get rid of parentheses
4x-8x+23+1=0
We add all the numbers together, and all the variables
-4x+24=0
We move all terms containing x to the left, all other terms to the right
-4x=-24
x=-24/-4
x=+6
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