3(2x+2)=(3*2x)+(3*2)=6x+6

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Solution for 3(2x+2)=(3*2x)+(3*2)=6x+6 equation: 



3(2x+2)=(3*2x)+(3*2)=6x+6

We move all terms to the left:

3(2x+2)-((3*2x)+(3*2))=0

We add all the numbers together, and all the variables

3(2x+2)-((+3*2x)+6)=0

We multiply parentheses

6x-((+3*2x)+6)+6=0



We calculate terms in parentheses: -((+3*2x)+6), so:

(+3*2x)+6

We get rid of parentheses

3*2x+6

Wy multiply elements

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

6x-6x-6+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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