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3(2x+2)=-4(2x-4)-3x
We move all terms to the left:
3(2x+2)-(-4(2x-4)-3x)=0
We multiply parentheses
6x-(-4(2x-4)-3x)+6=0
We calculate terms in parentheses: -(-4(2x-4)-3x), so:We get rid of parentheses
-4(2x-4)-3x
We add all the numbers together, and all the variables
-3x-4(2x-4)
We multiply parentheses
-3x-8x+16
We add all the numbers together, and all the variables
-11x+16
Back to the equation:
-(-11x+16)
6x+11x-16+6=0
We add all the numbers together, and all the variables
17x-10=0
We move all terms containing x to the left, all other terms to the right
17x=10
x=10/17
x=10/17
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