3(2x+2)=3(x-2)=

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Solution for 3(2x+2)=3(x-2)= equation: 



3(2x+2)=3(x-2)=

We move all terms to the left:

3(2x+2)-(3(x-2))=0

We multiply parentheses

6x-(3(x-2))+6=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

6x-3x+6+6=0

We add all the numbers together, and all the variables

3x+12=0

We move all terms containing x to the left, all other terms to the right

3x=-12

x=-12/3

x=-4

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