3(2x+2)=4(x+1)

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Solution for 3(2x+2)=4(x+1) equation: 



3(2x+2)=4(x+1)

We move all terms to the left:

3(2x+2)-(4(x+1))=0

We multiply parentheses

6x-(4(x+1))+6=0



We calculate terms in parentheses: -(4(x+1)), so:

4(x+1)

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

6x-4x-4+6=0

We add all the numbers together, and all the variables

2x+2=0

We move all terms containing x to the left, all other terms to the right

2x=-2

x=-2/2

x=-1

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