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3(2x+2-(5-3x))=13x+3(4x-2x)
We move all terms to the left:
3(2x+2-(5-3x))-(13x+3(4x-2x))=0
We add all the numbers together, and all the variables
3(2x+2-(-3x+5))-(13x+3(+2x))=0
We calculate terms in parentheses: -(13x+3(+2x)), so:We add all the numbers together, and all the variables
13x+3(+2x)
We multiply parentheses
13x+6x
We add all the numbers together, and all the variables
19x
Back to the equation:
-(19x)
-19x+3(2x+2-(-3x+5))=0
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