3(2x+3)+(2x-1)=7(x-4)

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Solution for 3(2x+3)+(2x-1)=7(x-4) equation:



3(2x+3)+(2x-1)=7(x-4)
We move all terms to the left:
3(2x+3)+(2x-1)-(7(x-4))=0
We multiply parentheses
6x+(2x-1)-(7(x-4))+9=0
We get rid of parentheses
6x+2x-(7(x-4))-1+9=0
We calculate terms in parentheses: -(7(x-4)), so:
7(x-4)
We multiply parentheses
7x-28
Back to the equation:
-(7x-28)
We add all the numbers together, and all the variables
8x-(7x-28)+8=0
We get rid of parentheses
8x-7x+28+8=0
We add all the numbers together, and all the variables
x+36=0
We move all terms containing x to the left, all other terms to the right
x=-36

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