3(2x+3)+11=(2x-6)-18

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Solution for 3(2x+3)+11=(2x-6)-18 equation: 



3(2x+3)+11=(2x-6)-18

We move all terms to the left:

3(2x+3)+11-((2x-6)-18)=0

We multiply parentheses

6x-((2x-6)-18)+9+11=0



We calculate terms in parentheses: -((2x-6)-18), so:

(2x-6)-18

We get rid of parentheses

2x-6-18

We add all the numbers together, and all the variables

2x-24

Back to the equation:

-(2x-24)



We add all the numbers together, and all the variables

6x-(2x-24)+20=0

We get rid of parentheses

6x-2x+24+20=0

We add all the numbers together, and all the variables

4x+44=0

We move all terms containing x to the left, all other terms to the right

4x=-44

x=-44/4

x=-11

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