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3(2x+3)+11=-2(x-6)-18
We move all terms to the left:
3(2x+3)+11-(-2(x-6)-18)=0
We multiply parentheses
6x-(-2(x-6)-18)+9+11=0
We calculate terms in parentheses: -(-2(x-6)-18), so:We add all the numbers together, and all the variables
-2(x-6)-18
We multiply parentheses
-2x+12-18
We add all the numbers together, and all the variables
-2x-6
Back to the equation:
-(-2x-6)
6x-(-2x-6)+20=0
We get rid of parentheses
6x+2x+6+20=0
We add all the numbers together, and all the variables
8x+26=0
We move all terms containing x to the left, all other terms to the right
8x=-26
x=-26/8
x=-3+1/4
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