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3(2x+3)+2(3x-4)=3(25+12)
We move all terms to the left:
3(2x+3)+2(3x-4)-(3(25+12))=0
We add all the numbers together, and all the variables
3(2x+3)+2(3x-4)-(337)=0
We add all the numbers together, and all the variables
3(2x+3)+2(3x-4)-337=0
We multiply parentheses
6x+6x+9-8-337=0
We add all the numbers together, and all the variables
12x-336=0
We move all terms containing x to the left, all other terms to the right
12x=336
x=336/12
x=28
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