3(2x+3)+2(4x+2)=41

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Solution for 3(2x+3)+2(4x+2)=41 equation:



3(2x+3)+2(4x+2)=41
We move all terms to the left:
3(2x+3)+2(4x+2)-(41)=0
We multiply parentheses
6x+8x+9+4-41=0
We add all the numbers together, and all the variables
14x-28=0
We move all terms containing x to the left, all other terms to the right
14x=28
x=28/14
x=2

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