3(2x+3)+2(4x+2)=41

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Solution for 3(2x+3)+2(4x+2)=41 equation: 



3(2x+3)+2(4x+2)=41

We move all terms to the left:

3(2x+3)+2(4x+2)-(41)=0

We multiply parentheses

6x+8x+9+4-41=0

We add all the numbers together, and all the variables

14x-28=0

We move all terms containing x to the left, all other terms to the right

14x=28

x=28/14

x=2

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