3(2x+3)+2(x+1)=27

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Solution for 3(2x+3)+2(x+1)=27 equation: 



3(2x+3)+2(x+1)=27

We move all terms to the left:

3(2x+3)+2(x+1)-(27)=0

We multiply parentheses

6x+2x+9+2-27=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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