3(2x+3)+2(x+1)=27

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Solution for 3(2x+3)+2(x+1)=27 equation:



3(2x+3)+2(x+1)=27
We move all terms to the left:
3(2x+3)+2(x+1)-(27)=0
We multiply parentheses
6x+2x+9+2-27=0
We add all the numbers together, and all the variables
8x-16=0
We move all terms containing x to the left, all other terms to the right
8x=16
x=16/8
x=2

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