3(2x+3)-6-8x=10x-2(2x-3)

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Solution for 3(2x+3)-6-8x=10x-2(2x-3) equation: 



3(2x+3)-6-8x=10x-2(2x-3)

We move all terms to the left:

3(2x+3)-6-8x-(10x-2(2x-3))=0

We add all the numbers together, and all the variables

-8x+3(2x+3)-(10x-2(2x-3))-6=0

We multiply parentheses

-8x+6x-(10x-2(2x-3))+9-6=0



We calculate terms in parentheses: -(10x-2(2x-3)), so:

10x-2(2x-3)

We multiply parentheses

10x-4x+6

We add all the numbers together, and all the variables

6x+6

Back to the equation:

-(6x+6)



We add all the numbers together, and all the variables

-2x-(6x+6)+3=0

We get rid of parentheses

-2x-6x-6+3=0

We add all the numbers together, and all the variables

-8x-3=0

We move all terms containing x to the left, all other terms to the right

-8x=3

x=3/-8

x=-3/8

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