3(2x+3)-7(x-4)=15x-11

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Solution for 3(2x+3)-7(x-4)=15x-11 equation: 



3(2x+3)-7(x-4)=15x-11

We move all terms to the left:

3(2x+3)-7(x-4)-(15x-11)=0

We multiply parentheses

6x-7x-(15x-11)+9+28=0

We get rid of parentheses

6x-7x-15x+11+9+28=0

We add all the numbers together, and all the variables

-16x+48=0

We move all terms containing x to the left, all other terms to the right

-16x=-48

x=-48/-16

x=+3

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