3(2x+3)=-36-27(x+2)

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Solution for 3(2x+3)=-36-27(x+2) equation:



3(2x+3)=-36-27(x+2)
We move all terms to the left:
3(2x+3)-(-36-27(x+2))=0
We multiply parentheses
6x-(-36-27(x+2))+9=0
We calculate terms in parentheses: -(-36-27(x+2)), so:
-36-27(x+2)
determiningTheFunctionDomain -27(x+2)-36
We multiply parentheses
-27x-54-36
We add all the numbers together, and all the variables
-27x-90
Back to the equation:
-(-27x-90)
We get rid of parentheses
6x+27x+90+9=0
We add all the numbers together, and all the variables
33x+99=0
We move all terms containing x to the left, all other terms to the right
33x=-99
x=-99/33
x=-3

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