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3(2x+3)=1/2(12x-18)
We move all terms to the left:
3(2x+3)-(1/2(12x-18))=0
Domain of the equation: 2(12x-18))!=0We multiply parentheses
x∈R
6x-(1/2(12x-18))+9=0
We multiply all the terms by the denominator
6x*2(12x-18))-(1+9*2(12x-18))=0
Wy multiply elements
12x^2(1+18x(1=0
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