3(2x+3)=2(x+1)23

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Solution for 3(2x+3)=2(x+1)23 equation: 



3(2x+3)=2(x+1)23

We move all terms to the left:

3(2x+3)-(2(x+1)23)=0

We multiply parentheses

6x-(2(x+1)23)+9=0



We calculate terms in parentheses: -(2(x+1)23), so:

2(x+1)23

We multiply parentheses

46x+46

Back to the equation:

-(46x+46)



We get rid of parentheses

6x-46x-46+9=0

We add all the numbers together, and all the variables

-40x-37=0

We move all terms containing x to the left, all other terms to the right

-40x=37

x=37/-40

x=-37/40

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