3(2x+3)=2(x+2)-3

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Solution for 3(2x+3)=2(x+2)-3 equation: 



3(2x+3)=2(x+2)-3

We move all terms to the left:

3(2x+3)-(2(x+2)-3)=0

We multiply parentheses

6x-(2(x+2)-3)+9=0



We calculate terms in parentheses: -(2(x+2)-3), so:

2(x+2)-3

We multiply parentheses

2x+4-3

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We get rid of parentheses

6x-2x-1+9=0

We add all the numbers together, and all the variables

4x+8=0

We move all terms containing x to the left, all other terms to the right

4x=-8

x=-8/4

x=-2

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