3(2x+3)=2(x+2)-3

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Solution for 3(2x+3)=2(x+2)-3 equation:



3(2x+3)=2(x+2)-3
We move all terms to the left:
3(2x+3)-(2(x+2)-3)=0
We multiply parentheses
6x-(2(x+2)-3)+9=0
We calculate terms in parentheses: -(2(x+2)-3), so:
2(x+2)-3
We multiply parentheses
2x+4-3
We add all the numbers together, and all the variables
2x+1
Back to the equation:
-(2x+1)
We get rid of parentheses
6x-2x-1+9=0
We add all the numbers together, and all the variables
4x+8=0
We move all terms containing x to the left, all other terms to the right
4x=-8
x=-8/4
x=-2

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