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3(2x+3)=4(3x-4)
We move all terms to the left:
3(2x+3)-(4(3x-4))=0
We multiply parentheses
6x-(4(3x-4))+9=0
We calculate terms in parentheses: -(4(3x-4)), so:We get rid of parentheses
4(3x-4)
We multiply parentheses
12x-16
Back to the equation:
-(12x-16)
6x-12x+16+9=0
We add all the numbers together, and all the variables
-6x+25=0
We move all terms containing x to the left, all other terms to the right
-6x=-25
x=-25/-6
x=4+1/6
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