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3(2x+3=13/5-x
We move all terms to the left:
3(2x+3-(13/5-x)=0
Domain of the equation: 5-x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-x)!=-5
x!=-5/1
x!=-5
x∈R
3(2x+3-(-1x+13/5)=0
We multiply all the terms by the denominator
3(2x+3-(-1x+13=0
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