3(2x+4)+3(3x+1)=38

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Solution for 3(2x+4)+3(3x+1)=38 equation: 



3(2x+4)+3(3x+1)=38

We move all terms to the left:

3(2x+4)+3(3x+1)-(38)=0

We multiply parentheses

6x+9x+12+3-38=0

We add all the numbers together, and all the variables

15x-23=0

We move all terms containing x to the left, all other terms to the right

15x=23

x=23/15

x=1+8/15

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