3(2x+4)+4(x-3)=5(x-4)

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Solution for 3(2x+4)+4(x-3)=5(x-4) equation: 



3(2x+4)+4(x-3)=5(x-4)

We move all terms to the left:

3(2x+4)+4(x-3)-(5(x-4))=0

We multiply parentheses

6x+4x-(5(x-4))+12-12=0



We calculate terms in parentheses: -(5(x-4)), so:

5(x-4)

We multiply parentheses

5x-20

Back to the equation:

-(5x-20)



We add all the numbers together, and all the variables

10x-(5x-20)=0

We get rid of parentheses

10x-5x+20=0

We add all the numbers together, and all the variables

5x+20=0

We move all terms containing x to the left, all other terms to the right

5x=-20

x=-20/5

x=-4

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