3(2x+4)+5(4x+2)+6=26x+28

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Solution for 3(2x+4)+5(4x+2)+6=26x+28 equation: 



3(2x+4)+5(4x+2)+6=26x+28

We move all terms to the left:

3(2x+4)+5(4x+2)+6-(26x+28)=0

We multiply parentheses

6x+20x-(26x+28)+12+10+6=0

We get rid of parentheses

6x+20x-26x-28+12+10+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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