3(2x+4)-2x=3(2+4x)+12

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Solution for 3(2x+4)-2x=3(2+4x)+12 equation: 



3(2x+4)-2x=3(2+4x)+12

We move all terms to the left:

3(2x+4)-2x-(3(2+4x)+12)=0

We add all the numbers together, and all the variables

3(2x+4)-2x-(3(4x+2)+12)=0

We add all the numbers together, and all the variables

-2x+3(2x+4)-(3(4x+2)+12)=0

We multiply parentheses

-2x+6x-(3(4x+2)+12)+12=0



We calculate terms in parentheses: -(3(4x+2)+12), so:

3(4x+2)+12

We multiply parentheses

12x+6+12

We add all the numbers together, and all the variables

12x+18

Back to the equation:

-(12x+18)



We add all the numbers together, and all the variables

4x-(12x+18)+12=0

We get rid of parentheses

4x-12x-18+12=0

We add all the numbers together, and all the variables

-8x-6=0

We move all terms containing x to the left, all other terms to the right

-8x=6

x=6/-8

x=-3/4

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